Construction Of Hyperbola
In this post, we'll learn about how can we draw a hyperbola. For example, we'll draw a hyperbola according to the given question.
Question: Point F is 50 mm from line AB. point P is moving in a plane
such that the ratio of its distances from F and line AB remains constant and equal to 2/3. draw locus of point P. { ECCENTRICITY = 2/3 }
Solution:
Procedure:
- Draw a vertical line AB and point F 50 mm from it.
- Divide the 50 mm distance into 5 parts.
- Name the 2nd part from F as V. It is 20mm and 30mm from F and AB line resp. It is first point giving ratio of it’s distances from F and AB 2/3 (i.e 20/30).
- For more points give the same ratio such as 30/45, 40/60, 50/75 etc.
- Taking 45,60 and 75mm distances from line AB, draw three vertical lines to the right side of it.
- Now with 30, 40 and 50mm distances in compass cut these lines above and below, with F as center.
- Join these points through V in smooth curve.
I hope you understood the concept. You can draw any kind of hyperbola by just following the given method. If you have any doubts, just let me know in the comment section! Till then keep learning, and keep improving!
0 Comments